Solve for h. 17 ≥ h + 6 ≥ 16 Write your answer as a compound inequality with integers. Choices: (A)11 > h ≥ 10 (B)h > 11 or h ≤ 10 (C)11 ≥ h ≥ 10 (D)h ≥ 11 or h ≤ 10

Analyze Inequality: Analyze the compound inequality 17 ≥ h + 6 ≥ 16. Which operation should we use to isolate h? In h + 6, 6 is being added to h. Subtraction should be used to isolate h.Subtract 6: Subtract 6 from all parts of the inequality 17 ≥ h + 6 ≥ 16. 17 - 6 ≥ h + 6 - 6 ≥ 16 - 6 11 ≥ h ≥ 10Write Compound Inequality: Write the answer as a compound inequality with integers. The inequality 11 ≥ h ≥ 10 matches one of the given choices.

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

h

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17 \geq h + 6 \geq 16

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Write your answer as a compound inequality with integers.

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Choices:

\newline

(A)

11 > h \geq 10

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(B)

h > 11

h \leq 10

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(C)

11 \geq h \geq 10

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(D)

h \geq 11

h \leq 10

Analyze Inequality: Analyze the compound inequality $17 \geq h + 6 \geq 16$ . Which operation should we use to isolate $h$ ? In $h + 6$ , $6$ is being added to $h$ . Subtraction should be used to isolate $h$ .
Subtract $6$ : Subtract $6$ from all parts of the inequality $17 \geq h + 6 \geq 16$ . $\newline$ $17 - 6 \geq h + 6 - 6 \geq 16 - 6$ $\newline$ $11 \geq h \geq 10$
Write Compound Inequality: Write the answer as a compound inequality with integers. $\newline$ The inequality $11 \geq h \geq 10$ matches one of the given choices.