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Solve for hh.\newline1(h+1)17-1(h + 1) \leq 17

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Q. Solve for hh.\newline1(h+1)17-1(h + 1) \leq 17
  1. Distribute 1-1: Distribute 1-1 across the parentheses in the inequality 1(h+1)17-1(h + 1) \leq 17.\newline1×h+1×117-1 \times h + -1 \times 1 \leq 17\newlineh117-h - 1 \leq 17
  2. Add 11: Add 11 to both sides of the inequality to isolate the term containing hh.\newlineh1+117+1-h - 1 + 1 \leq 17 + 1\newlineh18-h \leq 18
  3. Divide by 1-1: Divide both sides of the inequality by 1-1 to solve for hh. Remember that dividing by a negative number reverses the inequality sign.h1181\frac{-h}{-1} \geq \frac{18}{-1}h18h \geq -18

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