Solve for g. g - 20 > -4 or g + 19 ≤ 3 Write your answer as a compound inequality with integers. Choices: (A)16 ≥ g ≥ -16 (B)g > 16 or g ≤ -16 (C)16 > g ≥ -16 (D)g ≥ 16 or g ≤ -16

Isolate g in first part: Solve the first part of the compound inequality g - 20 > -4. To isolate g, we need to add 20 to both sides of the inequality. g - 20 + 20 > -4 + 20 g > 16Isolate g in second part: Solve the second part of the compound inequality g + 19 ≤ 3. To isolate g, we need to subtract 19 from both sides of the inequality. g + 19 - 19 ≤ 3 - 19 g ≤ -16Combine solutions: Combine the solutions from Step 1 and Step 2 to write the final compound inequality. The solution is g > 16 or g ≤ -16.

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Math Problems

Algebra 1

Solve compound inequalities

Full solution

Q. Solve for

g

\newline

g - 20 > -4

g + 19 \leq 3

\newline

Write your answer as a compound inequality with integers.

\newline

Choices:

\newline

(A)

16 \geq g \geq -16

\newline

(B)

g > 16

g \leq -16

\newline

(C)

16 > g \geq -16

\newline

(D)

g \geq 16

g \leq -16

Isolate $g$ in first part: Solve the first part of the compound inequality g - 20 > -4. To isolate $g$ , we need to add $20$ to both sides of the inequality. $\newline$ g - 20 + 20 > -4 + 20 g > 16
Isolate $g$ in second part: Solve the second part of the compound inequality $g + 19 \leq 3$ . To isolate $g$ , we need to subtract $19$ from both sides of the inequality. $\newline$ $g + 19 - 19 \leq 3 - 19$ $g \leq -16$
Combine solutions: Combine the solutions from Step $1$ and Step $2$ to write the final compound inequality. $\newline$ The solution is g > 16 or $g \leq -16$ .