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Solve for dd.\newline2d > 8

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Full solution

Q. Solve for dd.\newline2d>82d > 8
  1. Identify operation for isolation: 2d > 8\newlineWhich operation should we use to isolate dd?\newline22 is being multiplied by dd in 2d > 8.\newlineDivision should be used to isolate dd.
  2. Solve for dd: 2d > 8\newlineSolve for dd.\newline2d > 8\newline\frac{2d}{2} > \frac{8}{2}\newlined > 4

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