Solve for d. 2(d - 16) - 6 ≥ 2 ______

Distribute and Simplify: First, distribute the 2 into the parentheses: 2(d - 16) - 6 ≥ 2 becomes 2d - 32 - 6 ≥ 2.Combine Like Terms: Now, combine like terms on the left side: 2d - 32 - 6 becomes 2d - 38.Isolate 2d Term: Next, add 38 to both sides to isolate the 2d term: 2d - 38 + 38 ≥ 2 + 38.Solve for d: This simplifies to 2d ≥ 40.Final Solution: Finally, divide both sides by 2 to solve for d: 2d/2 ≥ 40/2.So, d ≥ 20 is the solution.

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Solve for $d$ . $\newline$ $2(d - 16) - 6 \geq 2$

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Algebra 1

Solve advanced linear inequalities

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Q. Solve for

d

\newline

2(d - 16) - 6 \geq 2

Distribute and Simplify: First, distribute the $2$ into the parentheses: $2(d - 16) - 6 \geq 2$ becomes $2d - 32 - 6 \geq 2$ .
Combine Like Terms: Now, combine like terms on the left side: $2d - 32 - 6$ becomes $2d - 38$ .
Isolate $2d$ Term: Next, add $38$ to both sides to isolate the $2d$ term: $2d - 38 + 38 \geq 2 + 38$ .
Solve for d: This simplifies to $2d \geq 40$ .
Final Solution: Finally, divide both sides by $2$ to solve for $d$ : $\frac{2d}{2} \geq \frac{40}{2}$ .
Final Solution: Finally, divide both sides by $2$ to solve for $d$ : $\frac{2d}{2} \geq \frac{40}{2}$ .So, $d \geq 20$ is the solution.