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Solve for cc. \newlinec+20c + 2 \leq 0 or c+1520c + 15 \geq 20\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A)c2c \leq -2 or c35c \geq 35\newline(B)c2c \leq -2 or c5c \geq 5\newline(C)c2c \leq 2 or c35c \geq 35\newline(D)c2c \leq 2 or c5c \geq 5

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Q. Solve for cc. \newlinec+20c + 2 \leq 0 or c+1520c + 15 \geq 20\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A)c2c \leq -2 or c35c \geq 35\newline(B)c2c \leq -2 or c5c \geq 5\newline(C)c2c \leq 2 or c35c \geq 35\newline(D)c2c \leq 2 or c5c \geq 5
  1. Subtract 22 to isolate c: To solve the inequality c+20c + 2 \leq 0, we need to isolate cc. We do this by subtracting 22 from both sides of the inequality.c+2202c + 2 - 2 \leq 0 - 2c2c \leq -2
  2. Subtract 1515 to isolate c: To solve the inequality c+1520c + 15 \geq 20, we need to isolate c. We do this by subtracting 1515 from both sides of the inequality.c+15152015c + 15 - 15 \geq 20 - 15c5c \geq 5
  3. Combine compound inequality: Now we combine the two parts of the compound inequality using "or" as given in the original problem. c2c \leq -2 or c5c \geq 5

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