Solve. –9x + 8y = –11 y = –7 (_____, _____)

Substitute y = -7: First, we substitute y = -7 into the equation –9x + 8y = –11. This gives us –9x + 8(-7) = –11. After simplifying, we get –9x - 56 = –11.Add 56 to isolate -9x: Next, we add 56 to both sides of the equation to isolate –9x. This gives us –9x = –11 + 56. After simplifying, we get –9x = 45.Divide by -9 for x: Finally, we divide both sides of the equation by -9 to solve for x. This gives us x = 45 / -9. After simplifying, we get x = -5.Substitute values for coordinate point: We found y = -7 and x = -5. Substitute these values in (x, y) to get the coordinate point. This gives us the coordinate point (-5, -7).

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Solve. $\newline$ $-9x + 8y = -11$ $\newline$ $y = -7$ $\newline$ (_, _)

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Algebra 2

Solve a system of equations using any method

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Q. Solve.

\newline

-9x + 8y = -11

\newline

y = -7

\newline

(_____, _____)

Substitute $y = -7$ : First, we substitute $y = -7$ into the equation $–9x + 8y = –11$ . This gives us $–9x + 8(-7) = –11$ . After simplifying, we get $–9x - 56 = –11$ .
Add $56$ to isolate $-9x$ : Next, we add $56$ to both sides of the equation to isolate $-9x$ . This gives us $-9x = -11 + 56$ . After simplifying, we get $-9x = 45$ .
Divide by $-9$ for $x$ : Finally, we divide both sides of the equation by $-9$ to solve for $x$ . This gives us $x = \frac{45}{-9}$ . After simplifying, we get $x = -5$ .
Substitute values for coordinate point: We found $y = -7$ and $x = -5$ . Substitute these values in $(x, y)$ to get the coordinate point. $\newline$ This gives us the coordinate point $(-5, -7)$ .