Solve. 8x + 3y = –11 y = –9 (_____, _____)

Given System of Equations: First, we are given a system of equations: 8x + 3y = –11 y = –9 We can substitute the value of y from the second equation into the first equation to find the value of x.Substitute y into first equation: Substitute y = –9 into the first equation: 8x + 3(-9) = –11 8x - 27 = –11Add 27 to isolate x term: Next, we add 27 to both sides of the equation to isolate the term with x: 8x - 27 + 27 = –11 + 27 8x = 16Divide by 8 to solve x: Now, we divide both sides by 8 to solve for x: 8x / 8 = 16 / 8 x = 2Final Solution: We have found the value of x to be 2. Since we already know the value of y is –9, we can write the solution as an ordered pair (x, y).

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve. $\newline$ $8x + 3y = -11$ $\newline$ $y = -9$ $\newline$ (_, _)

View step-by-step help

Home

Math Problems

Grade 8

Solve a system of equations using any method

Full solution

Q. Solve.

\newline

8x + 3y = -11

\newline

y = -9

\newline

(_____, _____)

Given System of Equations: First, we are given a system of equations: $\newline$ $8x + 3y = -11$ $\newline$ $y = -9$ $\newline$ We can substitute the value of $y$ from the second equation into the first equation to find the value of $x$ .
Substitute $y$ into first equation: Substitute $y = -9$ into the first equation: $\newline$ $8x + 3(-9) = -11$ $\newline$ $8x - 27 = -11$
Add $27$ to isolate x term: Next, we add $27$ to both sides of the equation to isolate the term with $x$ : $\newline$ $8x - 27 + 27 = -11 + 27$ $\newline$ $8x = 16$
Divide by $8$ to solve x: Now, we divide both sides by $8$ to solve for x: $\newline$ $\frac{8x}{8} = \frac{16}{8}$ $\newline$ $x = 2$
Final Solution: We have found the value of $x$ to be $2$ . Since we already know the value of $y$ is $-9$ , we can write the solution as an ordered pair $(x, y)$ .