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Select the outlier in the data set.\newline7,68,80,83,87,89,91,967, 68, 80, 83, 87, 89, 91, 96\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

Full solution

Q. Select the outlier in the data set.\newline7,68,80,83,87,89,91,967, 68, 80, 83, 87, 89, 91, 96\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 7,68,80,83,87,89,91,967, 68, 80, 83, 87, 89, 91, 96. An outlier is a data point that is significantly different from the rest of the data. We can often spot an outlier by looking for a number that is much smaller or larger than the rest. In this case, 77 is much smaller than all other numbers in the set, so it is likely the outlier.
  2. Confirm Outlier: To confirm that 77 is an outlier, we can calculate the interquartile range (IQR) and then determine the lower and upper bounds for outliers. However, since 77 is significantly lower than the rest of the data and the next smallest number is 6868, we can reasonably conclude that 77 is the outlier without further calculations.
  3. Calculate Mean with Outlier: Now, let's calculate the mean of the data set with and without the outlier to determine if the mean would increase or decrease upon its removal.\newlineFirst, calculate the mean with the outlier included:\newlineMean = (7+68+80+83+87+89+91+96)/8(7 + 68 + 80 + 83 + 87 + 89 + 91 + 96) / 8\newlineMean = (7+68+80+83+87+89+91+96)/8(7 + 68 + 80 + 83 + 87 + 89 + 91 + 96) / 8\newlineMean = 601/8601 / 8\newlineMean = 75.12575.125
  4. Calculate Mean without Outlier: Next, calculate the mean without the outlier:\newlineMean without outlier = (68+80+83+87+89+91+96)/7(68 + 80 + 83 + 87 + 89 + 91 + 96) / 7\newlineMean without outlier = (68+80+83+87+89+91+96)/7(68 + 80 + 83 + 87 + 89 + 91 + 96) / 7\newlineMean without outlier = 594/7594 / 7\newlineMean without outlier = 84.85784.857 approximately
  5. Compare Means: Compare the two means:\newlineMean with outlier = 75.12575.125\newlineMean without outlier = 84.85784.857\newlineSince the mean without the outlier is greater than the mean with the outlier, removing the outlier would increase the mean.
  6. Conclusion: The outlier in the data set is 77, and removing it would increase the mean.\newlineTherefore, the correct choice is (A)(A) increase.

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