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Mr. Hancock, the owner of two car dealerships in Newport, is holding a contest to see which one can sell the most cars. Newport Cars has already sold 55 cars, and Hancock's Autos has sold 1515 cars. Going forward, the salespeople at Newport Cars think they can sell 33 cars per day, whereas the salespeople at Hancock's Autos are aiming for sales of 22 cars per day. If the salespeople's predictions are accurate, it won't be long before the two dealerships are tied. How many cars will each lot have sold?\newlineWrite a system of equations, graph them, and type the solution.\newline____ cars\newline

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Q. Mr. Hancock, the owner of two car dealerships in Newport, is holding a contest to see which one can sell the most cars. Newport Cars has already sold 55 cars, and Hancock's Autos has sold 1515 cars. Going forward, the salespeople at Newport Cars think they can sell 33 cars per day, whereas the salespeople at Hancock's Autos are aiming for sales of 22 cars per day. If the salespeople's predictions are accurate, it won't be long before the two dealerships are tied. How many cars will each lot have sold?\newlineWrite a system of equations, graph them, and type the solution.\newline____ cars\newline
  1. Define Variables: Let's define the variables: Let x x be the number of days after the current sales. Newport Cars' total sales will be 5+3x 5 + 3x (since they start with 55 cars and sell 33 per day). Hancock's Autos' total sales will be 15+2x 15 + 2x (starting with 1515 cars and selling 22 per day).
  2. Set Up Equation: Set up the equation to find when both dealerships have sold the same number of cars: 5+3x=15+2x 5 + 3x = 15 + 2x .
  3. Solve for x: Solve for x x : Subtract 2x 2x from both sides to get 3x2x=155 3x - 2x = 15 - 5 , which simplifies to x=10 x = 10 .

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