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lim_(x rarr pi)cos(x)=?
Choose 1 answer:
(A) -1
(B) 0
(c) 1
(D) The limit doesn't exist.

limxπcos(x)=? \lim _{x \rightarrow \pi} \cos (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 00\newline(C) 11\newline(D) The limit doesn't exist.

Full solution

Q. limxπcos(x)=? \lim _{x \rightarrow \pi} \cos (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 00\newline(C) 11\newline(D) The limit doesn't exist.
  1. Substitution of xx: To find the limit of cos(x)\cos(x) as xx approaches π\pi, we can directly substitute xx with π\pi in the function cos(x)\cos(x), since cosine is a continuous function.
  2. Evaluation of cos(π)\cos(\pi): Substituting xx with π\pi, we get cos(π)\cos(\pi).
  3. Limit of cos(x)\cos(x) as xx approaches π\pi: The value of cos(π)\cos(\pi) is 1-1, as it is a well-known trigonometric value.
  4. Limit of cos(x)\cos(x) as xx approaches π\pi: The value of cos(π)\cos(\pi) is 1-1, as it is a well-known trigonometric value. Therefore, the limit of cos(x)\cos(x) as xx approaches π\pi is 1-1.

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