lim_(x rarr(pi)/(3))sin(x)=? Choose 1 answer: (A) (1)/(2) (B) (sqrt3)/(2) (c) sqrt3 (D) The limit doesn't exist.

Substitute x with π/3: To find the limit of sin(x) as x approaches π/3, we can directly substitute x with π/3 in the function sin(x), since the sine function is continuous everywhere. Calculate sin(π/3): Substituting x with π/3 in sin(x), we get sin(π/3). Use trigonometry: The exact value of sin(π/3) is known from trigonometry to be √3/2. Determine the limit: Therefore, the limit of sin(x) as x approaches π/3 is √3/2.

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lim_(x rarr(pi)/(3))sin(x)=?
Choose 1 answer:
(A)
(1)/(2)
(B)
(sqrt3)/(2)
(c)
sqrt3
(D) The limit doesn't exist.

$\lim _{x \rightarrow \frac{\pi}{3}} \sin (x)=?$ $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{1}{2}$ $\newline$ (B) $\frac{\sqrt{3}}{2}$ $\newline$ (C) $\sqrt{3}$ $\newline$ (D) The limit doesn't exist.

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

\lim _{x \rightarrow \frac{\pi}{3}} \sin (x)=?

\newline

Choose

1

answer:

\newline

(A)

\frac{1}{2}

\newline

(B)

\frac{\sqrt{3}}{2}

\newline

(C)

\sqrt{3}

\newline

(D) The limit doesn't exist.

Substitute $x$ with $\frac{\pi}{3}$ : To find the limit of $\sin(x)$ as $x$ approaches $\frac{\pi}{3}$ , we can directly substitute $x$ with $\frac{\pi}{3}$ in the function $\sin(x)$ , since the sine function is continuous everywhere.
Calculate $\sin(\frac{\pi}{3})$ : Substituting $x$ with $\frac{\pi}{3}$ in $\sin(x)$ , we get $\sin(\frac{\pi}{3})$ .
Use trigonometry: The exact value of $\sin(\frac{\pi}{3})$ is known from trigonometry to be $\frac{\sqrt{3}}{2}$ .
Determine the limit: Therefore, the limit of $\sin(x)$ as $x$ approaches $\frac{\pi}{3}$ is $\frac{\sqrt{3}}{2}$ .