Let f be the function defined by f(x)=2x. If three subintervals of equal length are used, what is the value of the right Riemann sum approximation for ∫12.52xdx ? Round to the nearest thousandth if necessary.Answer:
Q. Let f be the function defined by f(x)=2x. If three subintervals of equal length are used, what is the value of the right Riemann sum approximation for ∫12.52xdx ? Round to the nearest thousandth if necessary.Answer:
Determine Subinterval Length: We are given the function f(x)=2x and we need to approximate the integral from x=1 to x=2.5 using a right Riemann sum with three subintervals of equal length. First, we need to determine the length of each subinterval.The total interval length is 2.5−1=1.5. Since we are using three subintervals, the length of each subinterval is 31.5=0.5.
Find Right Endpoints: Next, we need to find the right endpoints of each subinterval. Since we start at x=1 and each subinterval is 0.5 units long, the right endpoints will be at x=1.5, x=2, and x=2.5.
Evaluate Function at Endpoints: Now we evaluate the function f(x)=2x at each of the right endpoints. This gives us the heights of the rectangles for the Riemann sum.f(1.5)=21.5f(2)=22f(2.5)=22.5
Calculate Function Values: We calculate the values of the function at these points:f(1.5)=21.5≈2.8284f(2)=22=4f(2.5)=22.5≈5.6569
Calculate Riemann Sum: The right Riemann sum is the sum of the areas of the rectangles. Each rectangle has a base of 0.5 (the subinterval length) and a height given by the function value at the right endpoint. So the Riemann sum is:Riemann sum ≈0.5×f(1.5)+0.5×f(2)+0.5×f(2.5)Riemann sum ≈0.5×2.8284+0.5×4+0.5×5.6569
Perform Calculations: Performing the calculations gives us:Riemann sum ≈0.5×2.8284+0.5×4+0.5×5.6569Riemann sum ≈1.4142+2+2.8284Riemann sum ≈6.2426
Round to Nearest Thousandth: Rounding to the nearest thousandth, we get: Riemann sum≈6.243
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