Let f be the function defined by f(x)=x2. If five subintervals of equal length are used, what is the value of the right Riemann sum approximation for ∫16x2dx ? Round to the nearest thousandth if necessary.Answer:
Q. Let f be the function defined by f(x)=x2. If five subintervals of equal length are used, what is the value of the right Riemann sum approximation for ∫16x2dx ? Round to the nearest thousandth if necessary.Answer:
Determine Subinterval Width: We are given the function f(x)=x2 and we need to approximate the integral from x=1 to x=6 using a right Riemann sum with five subintervals of equal length. The first step is to determine the width of each subinterval. The total interval length is 6−1=5. Since we are using five subintervals, the width of each subinterval (Δx) is 55=1.
Find Evaluation Points: Next, we need to find the x-values at which we will evaluate the function for the right Riemann sum. Since we are using the right endpoints and the first subinterval starts at x=1, the x-values will be 2, 3, 4, 5, and 6.
Evaluate Function: Now we evaluate the function f(x)=x2 at each of these x-values:f(2)=22=1f(3)=32≈0.667f(4)=42=0.5f(5)=52=0.4f(6)=62≈0.333
Calculate Rectangle Areas: We then multiply each function value by the width of the subintervals (Δx=1) to get the area of each rectangle in the Riemann sum:Area at x=2: 1×Δx=1×1=1Area at x=3: 0.667×Δx=0.667×1≈0.667Area at x=4: 0.5×Δx=0.5×1=0.5Area at x=5: 0.4×Δx=0.4×1=0.4Area at x=6: $\(0\).\(333\) \times \Delta x = \(0\).\(333\) \times \(1\) \approx \(0\).\(333\)
Sum Rectangle Areas: Finally, we sum the areas of all the rectangles to get the right Riemann sum approximation for the integral:\(\newline\)Right Riemann sum = \(1 + 0.667 + 0.5 + 0.4 + 0.333 \approx 2.9\)
Round Final Result: We round the result to the nearest thousandth as instructed: Right Riemann sum \(\approx 2.900\)
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