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Let’s check out your problem:
Let
E
=
{
2
,
6
}
E = \{2, 6\}
E
=
{
2
,
6
}
and
F
=
{
1
,
3
,
4
,
5
,
7
}
F = \{1, 3, 4, 5, 7\}
F
=
{
1
,
3
,
4
,
5
,
7
}
. What is
E
∩
F
E \cap F
E
∩
F
?
\newline
Choices:
\newline
(A)
{
1
,
2
,
5
,
6
}
\{1, 2, 5, 6\}
{
1
,
2
,
5
,
6
}
\newline
(B)
{
1
,
2
,
5
,
6
,
7
}
\{1, 2, 5, 6, 7\}
{
1
,
2
,
5
,
6
,
7
}
\newline
(C)
{
1
,
2
,
3
,
4
,
5
,
6
,
7
}
\{1, 2, 3, 4, 5, 6, 7\}
{
1
,
2
,
3
,
4
,
5
,
6
,
7
}
\newline
(D)
∅
\emptyset
∅
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Math Problems
Algebra 2
Is (x, y) a solution to the system of equations?
Full solution
Q.
Let
E
=
{
2
,
6
}
E = \{2, 6\}
E
=
{
2
,
6
}
and
F
=
{
1
,
3
,
4
,
5
,
7
}
F = \{1, 3, 4, 5, 7\}
F
=
{
1
,
3
,
4
,
5
,
7
}
. What is
E
∩
F
E \cap F
E
∩
F
?
\newline
Choices:
\newline
(A)
{
1
,
2
,
5
,
6
}
\{1, 2, 5, 6\}
{
1
,
2
,
5
,
6
}
\newline
(B)
{
1
,
2
,
5
,
6
,
7
}
\{1, 2, 5, 6, 7\}
{
1
,
2
,
5
,
6
,
7
}
\newline
(C)
{
1
,
2
,
3
,
4
,
5
,
6
,
7
}
\{1, 2, 3, 4, 5, 6, 7\}
{
1
,
2
,
3
,
4
,
5
,
6
,
7
}
\newline
(D)
∅
\emptyset
∅
Intersection Definition:
The intersection of two sets, denoted by
E
∩
F
E \cap F
E
∩
F
, is the set of elements that are common to both
E
E
E
and
F
F
F
.
List Set E:
We list the elements of set E, which are
{
2
,
6
}
\{2, 6\}
{
2
,
6
}
.
List Set F:
We list the elements of set F, which are
{
1
,
3
,
4
,
5
,
7
}
\{1, 3, 4, 5, 7\}
{
1
,
3
,
4
,
5
,
7
}
.
Find Common Elements:
We look for common elements between set
E
E
E
and set
F
F
F
. There are no common elements since
2
2
2
and
6
6
6
are not in set
F
F
F
.
Intersection Result:
Since there are no common elements, the intersection of
E
E
E
and
F
F
F
is the empty set, denoted by
∅
\emptyset
∅
.
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x
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\newline
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Question
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\newline
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y
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\text{(A) consistent and independent}
(A) consistent and independent
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\text{(B) consistent and dependent}
(B) consistent and dependent
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Solve using elimination.
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_
_
_
)
(\_\_\_\_, \_\_\_\_)
(
____
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Solve.
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x
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y
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Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
\newline
At a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases
3
3
3
hot dog meals and
3
3
3
hamburger meals, paying a total of
$
36
\$36
$36
. Mr. Hogan buys
1
1
1
hot dog meal and
3
3
3
hamburger meals, spending
$
26
\$26
$26
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\newline
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\$
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Solve the system of equations by substitution.
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−
3
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z
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−
3
x
−
y
−
3
z
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5
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−
y
+
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z
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19
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x
−
y
+
3
z
=
19
\newline
(____.____,____)
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Question
Solve the system of equations by elimination.
\newline
x
−
3
y
−
2
z
=
10
x - 3y - 2z = 10
x
−
3
y
−
2
z
=
10
\newline
3
x
+
2
y
+
2
z
=
14
3x + 2y + 2z = 14
3
x
+
2
y
+
2
z
=
14
\newline
2
x
−
3
y
−
2
z
=
16
2x - 3y - 2z = 16
2
x
−
3
y
−
2
z
=
16
\newline
(
_
,
_
,
_
)
(\_,\_,\_)
(
_
,
_
,
_
)
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Question
Solve the system of equations.
\newline
y
=
x
2
+
36
x
+
3
y = x^2 + 36x + 3
y
=
x
2
+
36
x
+
3
\newline
y
=
22
x
−
37
y = 22x - 37
y
=
22
x
−
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\newline
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\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
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,
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Question
Solve the system of equations.
\newline
y
=
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x
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=
−
x
−
24
\newline
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2
+
y
2
=
488
x^2 + y^2 = 488
x
2
+
y
2
=
488
\newline
Write the coordinates in exact form. Simplify all fractions and radicals.
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
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