Is (3,6) a solution to this system of equations? y = 2x + 1 y = 4x + 6 Choices: (A)yes (B)no

Substitute and Check: First, we will substitute the point (3,6) into the first equation and check if it holds true. The first equation is y = 2x + 1. If we substitute x=3 and y=6, we get 6 = 2*3 + 1. Verify First Equation: After performing the calculation, we find that 6 = 6 + 1, which simplifies to 6 = 7. This is not true. Therefore, the point (3,6) does not satisfy the first equation. No Solution: Since the point (3,6) does not satisfy the first equation, there is no need to check the second equation. The point (3,6) cannot be a solution to the system of equations if it does not satisfy both equations.

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Is $(3,6)$ a solution to this system of equations? $\newline$ $y = 2x + 1$ $\newline$ $y = 4x + 6$ $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

Q. Is

(3,6)

a solution to this system of equations?

\newline

y = 2x + 1

\newline

y = 4x + 6

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute and Check: First, we will substitute the point $(3,6)$ into the first equation and check if it holds true. The first equation is $y = 2x + 1$ . If we substitute $x=3$ and $y=6$ , we get $6 = 2\times3 + 1$ .
Verify First Equation: After performing the calculation, we find that $6 = 6 + 1$ , which simplifies to $6 = 7$ . This is not true. Therefore, the point $(3,6)$ does not satisfy the first equation.
No Solution: Since the point $(3,6)$ does not satisfy the first equation, there is no need to check the second equation. The point $(3,6)$ cannot be a solution to the system of equations if it does not satisfy both equations.