Is (1,7) a solution to this system of equations? y = 5x + 5 y = 6x + 1 Choices: (A)yes (B)no

Substitute and Check: First, we will substitute the point (1,7) into the first equation and check if it holds true. The first equation is y = 5x + 5. If we substitute x=1 and y=7, we get 7 = 5*1 + 5. Calculation Result: After performing the calculation, we find that 7 = 5 + 5, which is not true because 5 + 5 equals 10, not 7. Therefore, the point (1,7) does not satisfy the first equation. Conclusion: Since the point (1,7) does not satisfy the first equation, there is no need to check the second equation. We can conclude that (1,7) is not a solution to the system of equations.

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Is $(1,7)$ a solution to this system of equations? $\newline$ $y = 5x + 5$ $\newline$ $y = 6x + 1$ $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

Q. Is

(1,7)

a solution to this system of equations?

\newline

y = 5x + 5

\newline

y = 6x + 1

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute and Check: First, we will substitute the point $(1,7)$ into the first equation and check if it holds true. The first equation is $y = 5x + 5$ . If we substitute $x=1$ and $y=7$ , we get $7 = 5 \times 1 + 5$ .
Calculation Result: After performing the calculation, we find that $7 = 5 + 5$ , which is not true because $5 + 5$ equals $10$ , not $7$ . Therefore, the point $(1,7)$ does not satisfy the first equation.
Conclusion: Since the point $(1,7)$ does not satisfy the first equation, there is no need to check the second equation. We can conclude that $(1,7)$ is not a solution to the system of equations.