Q. Is (1,7) a solution to this system of equations?y=5x+2y=7x+3Choices:(A)yes(B)no
Substitute and Verify: First, we will substitute the point (1,7) into the first equation and check if it holds true. The first equation is y=5x+2. If we substitute x=1 and y=7, we get 7=5×1+2.
First Equation Check: After performing the calculation, we find that 7=5+2, which simplifies to 7=7, which is true. Therefore, the point (1,7) satisfies the first equation.
Second Equation Check: Next, we will substitute the point (1,7) into the second equation and check if it holds true. The second equation is y=7x+3. If we substitute x=1 and y=7, we get 7=7×1+3.
Solution Verification: After performing the calculation, we find that 7=7+3, which simplifies to 7=10, which is not true. Therefore, the point (1,7) does not satisfy the second equation.
Final Conclusion: Since the point (1,7) does not satisfy both equations, it is not a solution to the system of equations.
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