Given integral: We are given the integral to evaluate:∫(x+100)320000dxFirst, we will use a substitution method to simplify the integral.Let u=x+100, then du=dx.
Substitution method: Now, we rewrite the integral in terms of u:∫u320000du
Rewrite in terms of u: The integral of u320000 is the same as 20000 times the integral of u−3. We can use the power rule for integration, which states that ∫undu=n+1un+1 for n=−1.
Apply power rule: Applying the power rule, we get: 20000×∫u−3du=20000×(−2u−2)
Simplify expression: Simplify the expression:=−10000⋅u−2
Substitute back for u: Now, we substitute back for u to get the integral in terms of x:=−10000×(x+100)−2
Add constant of integration: Finally, we add the constant of integration C to get the indefinite integral:=−(x+100)210000+C
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