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1eetan1xxdx\int_{\frac{1}{e}}^{e} \frac{\tan^{-1}x}{x}dx

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Q. 1eetan1xxdx\int_{\frac{1}{e}}^{e} \frac{\tan^{-1}x}{x}dx
  1. Identify Integral: Identify the integral to be solved.\newlineWe need to evaluate the integral of the function tan1xx\frac{\tan^{-1}x}{x} within the limits from 1e\frac{1}{e} to ee.
  2. Check Standard Formula: Check if there is a standard integration formula that can be applied.\newlineThe integral of (tan1x)/(x)(\tan^{-1}x)/(x) does not match any standard integration formula directly. Therefore, we will need to use integration techniques to solve it.
  3. Apply Integration by Parts: Apply integration by parts. Integration by parts is given by the formula udv=uvvdu\int u \, dv = uv - \int v \, du, where uu and dvdv are parts of the integrand. We choose u=tan1xu = \tan^{-1}x (which gives du=11+x2du = \frac{1}{1+x^2}dx) and dv=dxxdv = \frac{dx}{x} (which gives v=lnxv = \ln|x|).
  4. Perform Integration: Perform the integration by parts.\newlineUsing the formula from Step 33, we have:\newlinetan1xxdx=tan1xlnxlnx11+x2dx\int\frac{\tan^{-1}x}{x} dx = \tan^{-1}x \cdot \ln|x| - \int\ln|x| \cdot \frac{1}{1+x^2} dx
  5. Evaluate Remaining Integral: Evaluate the remaining integral.\newlineThe integral lnx(11+x2)dx\int \ln|x| \cdot \left(\frac{1}{1+x^2}\right) dx is not elementary and cannot be expressed in terms of elementary functions. This suggests that there might be a mistake in the choice of uu and dvdv in the integration by parts.

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