In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 150 , and then went up by 6% in 2011 . How many robberies were there in Springfield in 2011? Answer:

Question

In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 150 , and then went up by  6% in 2011 . How many robberies were there in Springfield in 2011? Answer:

Bytelearn · Accepted Answer

Identify initial number and increase: Identify the initial number of robberies and the percentage increase. The initial number of robberies in Springfield in 2010 was 150. The percentage increase in robberies from 2010 to 2011 is 6%.Calculate actual increase: Calculate the actual increase in the number of robberies. To find the actual increase, multiply the initial number of robberies by the percentage increase. Increase in robberies = 150 * (6/100) = 9Calculate total robberies: Calculate the total number of robberies in 2011. To find the total number of robberies in 2011, add the increase to the initial number of robberies. Total robberies in 2011 = Initial robberies + Increase in robberies Total robberies in 2011 = 150 + 9 = 159

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $150$ , and then went up by $6 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer:

Full solution

More problems from Percent of change: word problems

Related topics

In a newspaper, it was reported that the number of yearly robberies in Springfield in 201020102010 was 150150150 , and then went up by 6% 6 \% 6% in 201120112011 . How many robberies were there in Springfield in 201120112011?\newlineAnswer:

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $150$ , and then went up by $6 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer: