In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 150 , and then went down by 50% in 2011 . How many robberies were there in Springfield in 2011? Answer:

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In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 150 , and then went down by  50% in 2011 . How many robberies were there in Springfield in 2011? Answer:

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Identify Initial Number: Identify the initial number of robberies in Springfield in 2010. The reported number of yearly robberies in Springfield in 2010 was 150.Calculate Decrease: Calculate the decrease in the number of robberies in 2011. The robberies went down by 50% in 2011. To find the decrease, we calculate 50% of 150. Decrease = 50% of 150 = 0.50 * 150Perform Calculation: Perform the calculation to find the decrease in the number of robberies. Decrease = 0.50 * 150 = 75 robberiesCalculate Number in 2011: Calculate the number of robberies in Springfield in 2011. To find the number of robberies in 2011, subtract the decrease from the number of robberies in 2010. Number of robberies in 2011 = 150 - 75Perform Subtraction: Perform the subtraction to find the final number of robberies in 2011. Number of robberies in 2011 = 150 - 75 = 75 robberies

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $150$ , and then went down by $50 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer:

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In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $150$ , and then went down by $50 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer: