In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 200 , and then went down by 4% in 2011 . How many robberies were there in Springfield in 2011? Answer:

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In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 200 , and then went down by  4% in 2011 . How many robberies were there in Springfield in 2011? Answer:

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Identify initial number and decrease: Identify the initial number of robberies and the percentage decrease. The initial number of robberies in Springfield in 2010 was 200. The percentage decrease in robberies from 2010 to 2011 was 4%.Calculate actual decrease: Calculate the actual decrease in the number of robberies. To find the actual decrease, multiply the initial number of robberies by the percentage decrease. Decrease in robberies = 200 robberies * (4/100) = 8 robberies.Calculate number in 2011: Calculate the number of robberies in Springfield in 2011. Subtract the decrease in robberies from the initial number of robberies to find the number in 2011. Number of robberies in 2011 = 200 robberies - 8 robberies = 192 robberies.

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $200$ , and then went down by $4 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer:

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In a newspaper, it was reported that the number of yearly robberies in Springfield in 201020102010 was 200200200 , and then went down by 4% 4 \% 4% in 201120112011 . How many robberies were there in Springfield in 201120112011?\newlineAnswer:

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $200$ , and then went down by $4 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer: