How many solutions does the system of equations below have?3x−3y+3z=−18x−y+z=−6−2x+2y−2z=12Choices:(A)no solution(B)one solution(C)infinitely many solutions
Q. How many solutions does the system of equations below have?3x−3y+3z=−18x−y+z=−6−2x+2y−2z=12Choices:(A)no solution(B)one solution(C)infinitely many solutions
Simplify Equations: First, let's simplify the equations by dividing the first and third equations by 3 and −2, respectively, to see if they are multiples of the second equation.3x−3y+3z=−18 becomes x−y+z=−6 after dividing by 3.−2x+2y−2z=12 becomes x−y+z=−6 after dividing by −2.
Check for Multiples: Now we have:1. x−y+z=−62. x−y+z=−63. x−y+z=−6All three equations are the same, which means every point on the line of the second equation is also on the lines of the first and third equations.
Identify Same Equations: Since all three equations represent the same line, the system has infinitely many solutions because there are an infinite number of points where these lines intersect (which is the line itself).
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