How many solutions does the system of equations below have?2x+y+2z=11−2x−3y+3z=192x+3y−3z=15Choices:(A)no solution(B)one solution(C)infinitely many solutions
Q. How many solutions does the system of equations below have?2x+y+2z=11−2x−3y+3z=192x+3y−3z=15Choices:(A)no solution(B)one solution(C)infinitely many solutions
Combine equations to eliminate x: Add the first and third equations to eliminate x. (2x+y+2z)+(2x+3y−3z)=11+15 4x+4y−z=26
Add equations to eliminate y: Now, add the second equation to the new equation we got from the first step.(−2x−3y+3z)+(4x+4y−z)=19+262x+y+2z=45
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