Happy Town had a circus performance during the school holidays. 20% of the people were performers and the rest were audience. Female performers were twice the number of male performers. 60% of the audience were male and there were 1200 more male audience than female audience. After some males left the circus, 20% of the remaining people in the circus were male. How many males left the circus?

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Denote Total People: Let's denote the total number of people in the circus as T. According to the problem, 20% of the people were performers. Therefore, the number of audience members is 80% of T. Number of audience = 0.8 * TCalculate Male and Female Audience: We are given that 60% of the audience were male and there were 1200 more male audience than female audience. Let's denote the number of male audience as M_a and the number of female audience as F_a. We can set up the following equation: M_a = 0.6 * (Number of audience) F_a = M_a - 1200 Substituting the expression for the number of audience from Step 1, we get: M_a = 0.6 * (0.8 * T) F_a = 0.6 * (0.8 * T) - 1200Equation for Male and Female Audience: Since M_a is 1200 more than F_a, we can write: 0.6 * (0.8 * T) = (0.6 * (0.8 * T) - 1200) + 1200 This simplifies to: 0.6 * (0.8 * T) = 0.6 * (0.8 * T) This is a tautology and does not help us find T. We need to find another way to express the relationship between M_a and F_a.

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