From 1945 to 2008, one country's per capita gross domestic product (GDPPC) increased about 6% per year, ending at $19,600. For the next few years, the growth slowed to an increase of about $1,300 per year. To the nearest dollar, how much less did the GDPPC grow during the next 6 years than it would have if it had maintained its earlier growth rate?□
Q. From 1945 to 2008, one country's per capita gross domestic product (GDPPC) increased about 6% per year, ending at $19,600. For the next few years, the growth slowed to an increase of about $1,300 per year. To the nearest dollar, how much less did the GDPPC grow during the next 6 years than it would have if it had maintained its earlier growth rate?□
Calculate GDPPC Growth: First, we need to calculate the GDPPC growth over the next 6 years if it had maintained the 6% per year growth rate.The formula for compound growth is:GDPPCend=GDPPCstart×(1+growth_rate)number_of_yearsHere, GDPPCstart is $19,600, growth_rate is 6% or 0.06, and number_of_years is 6.
Perform Calculation: Now, we perform the calculation:GDPPCend=$(19,600)×(1+0.06)6Using a calculator, we find:GDPPCend≈$(19,600)×(1.418519)GDPPCend≈$(27,803.17)This is the GDPPC at the end of 6 years with a 6% growth rate per year.
Calculate Slower Growth: Next, we calculate the GDPPC growth with the slower rate of $1,300 per year for 6 years.The formula for linear growth is:GDPPCend=GDPPCstart+(increase_per_year×number_of_years)Here, GDPPCstart is $19,600, increase_per_year is $1,300, and number_of_years is 6.
Find Difference: Now, we perform the calculation:GDPPCend = $19,600 + $1,300×6GDPPCend = $19,600 + $7,800GDPPCend = $27,400This is the GDPPC at the end of 6 years with a growth of $1,300 per year.
Perform Subtraction: Finally, we find the difference between the GDPPC growth at the 6% rate and the slower $1,300 per year rate.Difference = GDPPC\_end (6% growth) - GDPPC\_end ($1,300/year growth)Difference = $27,803.17 - $27,400
Perform Subtraction: Finally, we find the difference between the GDPPC growth at the 6\% rate and the slower (\$)\(1\),\(300\) per year rate.\(\newline\)Difference = GDPPC\_end (\(6\)\% growth) - GDPPC\_end (\(\$\)\(1\),\(300\)/year growth)\(\newline\)Difference = \(\$27,803.17 - \$27,400\)Now, we perform the subtraction:\(\newline\)Difference \(\approx \$403.17\)\(\newline\)To the nearest dollar, the GDPPC grew \(\$403\) less during the next \(6\) years than it would have if it had maintained its earlier growth rate of \(6\)\% per year.
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