Q. Find the value of the following expression and round to the nearest integer:n=1∑21100(0.96)n−1Answer:
Given values and formula: We are asked to evaluate a geometric series with the first term a=100 and the common ratio r=0.96. The sum of the first n terms of a geometric series is given by the formula Sn=(1−r)a(1−rn), where n is the number of terms. In this case, we want to find the sum of the first 21 terms.
Calculate power of 0.9621: First, let's plug in the values into the formula for the sum of a geometric series: S21=100(1−0.9621)/(1−0.96).
Substitute values into formula: Now, we calculate the power of 0.9621 using a calculator.
Perform subtraction in numerator: After calculating, we find that 0.9621 is approximately 0.45289.
Perform subtraction in denominator: We substitute this value back into the formula: S21=(1−0.96)100(1−0.45289).
Divide numerator by denominator: Now, we perform the subtraction in the numerator: 1−0.45289=0.54711.
Perform division and multiplication: Next, we perform the subtraction in the denominator: 1−0.96=0.04.
Round to nearest integer: We now divide the numerator by the denominator: S21=100×0.54711/0.04.
Round to nearest integer: We now divide the numerator by the denominator: S21=100×0.54711/0.04. Performing the division and multiplication, we get S21=100×13.6775.
Round to nearest integer: We now divide the numerator by the denominator: S21=100×0.54711/0.04. Performing the division and multiplication, we get S21=100×13.6775. Multiplying 100 by 13.6775 gives us S21=1367.75.
Round to nearest integer: We now divide the numerator by the denominator: S21=100×0.54711/0.04. Performing the division and multiplication, we get S21=100×13.6775. Multiplying 100 by 13.6775 gives us S21=1367.75. Finally, we round 1367.75 to the nearest integer, which is 1368.
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