Q. Find the value of the following expression and round to the nearest integer:n=1∑6240(1.03)nAnswer:
Given Series Information: We are given a geometric series with the first term a=40(1.03)1 and the common ratio r=1.03. The sum of the first n terms of a geometric series is given by the formula Sn=(1−r)a(1−rn), where n is the number of terms. We need to find the sum of 62 terms.
Calculate First Term: First, let's calculate the first term of the series: a=40(1.03)1=40×1.03.
Calculate Common Ratio: Now, we calculate the common ratio r, which is 1.03. Since it is greater than 1, the series is increasing.
Calculate 62nd Term: Next, we calculate the 62nd term of the series using the formula for the nth term of a geometric series, which is an=a⋅r(n−1). So, a62=40⋅1.03(62−1)=40⋅1.0361.
Use Sum Formula: Now we can use the sum formula for a geometric series: S62=a(1−r62)/(1−r). Plugging in the values we have S62=40×1.03(1−1.0362)/(1−1.03).
Perform Calculations: We perform the calculations for the sum: S62=40×1.03(1−1.0362)/(1−1.03)=40×1.03(1−1.0362)/(−0.03).
Calculate Exponentiation: We need to calculate 1.0362. This is a large exponentiation, and it's best to use a calculator for this step to avoid any math errors.
Substitute Value: After calculating 1.0362, we substitute this value back into the sum formula to get the exact value of the sum.
Round to Nearest Integer: Finally, we round the result to the nearest integer as the question prompt asks for the value rounded to the nearest integer.
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