Q. Find the numerical value of the log expression.loga=−12logb=−8logc=−6loga9b3c3Answer:
Given values: We are given the values of loga, logb, and logc as −12, −8, and −6 respectively. We need to find the value of log(a9b3c3).
Simplify expression: First, let's simplify the expression inside the logarithm. The square root of a product can be written as the product of the square roots, and the square root of a power can be written as the power with half the exponent. So, b3c3=b3⋅c3=b3/2⋅c3/2.
Rewrite using properties: Now, we can rewrite the logarithm using the properties of logarithms. The logarithm of a quotient is the difference of the logarithms, and the logarithm of a product is the sum of the logarithms. So, log(a9b3c3)=log(b3/2⋅c3/2)−log(a9).
Apply power rule: Applying the power rule for logarithms, which states that log(xy)=y⋅log(x), we get log(b3/2⋅c3/2)−log(a9)=23⋅log(b)+23⋅log(c)−9⋅log(a).
Substitute values: Substituting the given values of loga, logb, and logc into the expression, we get 23⋅(−8)+23⋅(−6)−9⋅(−12).
Perform calculations: Performing the calculations, we have 23⋅(−8)=−12, 23⋅(−6)=−9, and 9⋅(−12)=−108. So, the expression simplifies to −12+(−9)−(−108).
Final numerical value: Finally, we add the numbers together to get the numerical value of the log expression: −12−9+108=87.
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