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f^(')(x)=-10x^(4)+8x^(3) and f(1)=9. f(0)=

f′(x)=−10x4+8x3 f^{\prime}(x)=-10 x^{4}+8 x^{3} and f(1)=9 f(1)=9 .\newlinef(0)= f(0)=

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Full solution

Q. f′(x)=−10x4+8x3 f^{\prime}(x)=-10 x^{4}+8 x^{3} and f(1)=9 f(1)=9 .\newlinef(0)= f(0)=
  1. Plug in x=0x=0: To find f(0)f(0), we just plug in 00 for xx in the function f(x)f(x).\newlinef(0)=−10(0)4+8(0)3f(0) = -10(0)^4 + 8(0)^3
  2. Simplify powers of 00: Simplify the expression by calculating the powers of 00.\newline−10(0)4=−10×0=0-10(0)^4 = -10 \times 0 = 0\newline8(0)3=8×0=08(0)^3 = 8 \times 0 = 0
  3. Add results: Add the results together. f(0)=0+0f(0) = 0 + 0
  4. Final answer: So, f(0)f(0) equals 00.

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