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f(1) = -16, f(n) = f(n-1) * (-(1)/(2)), f(3) = ◻

{f(1)=−16f(n)=f(n−1)⋅(−12)f(3)=□ \begin{array}{l}\left\{\begin{array}{l}f(1)=-16 \\ f(n)=f(n-1) \cdot\left(-\frac{1}{2}\right)\end{array}\right. \\ f(3)=\square\end{array}

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