Evaluate the summation below. sum_(t=1)^(4)(-t^(2)-3) Answer:

Write and Evaluate for t=1: Write down the summation expression and evaluate it for t=1. The expression is (-t^2 - 3). For t=1, the expression becomes: -1^2 - 3 = -1 - 3 = -4.Evaluate for t=2: Evaluate the expression for t=2. For t=2, the expression becomes: -2^2 - 3 = -4 - 3 = -7.Evaluate for t=3: Evaluate the expression for t=3. For t=3, the expression becomes: -3^2 - 3 = -9 - 3 = -12.Evaluate for t=4: Evaluate the expression for t=4. For t=4, the expression becomes: -4^2 - 3 = -16 - 3 = -19.Add and Sum: Add up the values obtained for t=1, t=2, t=3, and t=4. Sum = (-4) + (-7) + (-12) + (-19).Perform Addition: Perform the addition to find the total sum. Sum = -4 - 7 - 12 - 19 = -42.

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Evaluate the summation below.

sum_(t=1)^(4)(-t^(2)-3)
Answer:

Evaluate the summation below. $\newline$ $\sum_{t=1}^{4}\left(-t^{2}-3\right)$ $\newline$ Answer:

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Calculus

Evaluate definite integrals using the chain rule

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Q. Evaluate the summation below.

\newline

\sum_{t=1}^{4}\left(-t^{2}-3\right)

\newline

Answer:

Write and Evaluate for $t=1$ : Write down the summation expression and evaluate it for $t=1$ . The expression is $(-t^2 - 3)$ . For $t=1$ , the expression becomes: $-1^2 - 3 = -1 - 3 = -4$ .
Evaluate for $t=2$ : Evaluate the expression for $t=2$ . For $t=2$ , the expression becomes: $-2^2 - 3 = -4 - 3 = -7$ .
Evaluate for $t=3$ : Evaluate the expression for $t=3$ . For $t=3$ , the expression becomes: $-3^2 - 3 = -9 - 3 = -12$ .
Evaluate for $t=4$ : Evaluate the expression for $t=4$ . For $t=4$ , the expression becomes: $-4^2 - 3 = -16 - 3 = -19$ .
Add and Sum: Add up the values obtained for $t=1$ , $t=2$ , $t=3$ , and $t=4$ . $\newline$ Sum = $(-4) + (-7) + (-12) + (-19)$ .
Perform Addition: Perform the addition to find the total sum. $\newline$ Sum = $-4 - 7 - 12 - 19 = -42$ .