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Evaluate the summation below.

sum_(t=0)^(3)(-5-9t^(2))
Answer:

Evaluate the summation below.\newlinet=03(59t2) \sum_{t=0}^{3}\left(-5-9 t^{2}\right) \newlineAnswer:

Full solution

Q. Evaluate the summation below.\newlinet=03(59t2) \sum_{t=0}^{3}\left(-5-9 t^{2}\right) \newlineAnswer:
  1. Write Summation Formula: Write down the summation formula that needs to be evaluated.\newlineThe summation is given by:\newlinet=03(59t2)\sum_{t=0}^{3}(-5-9t^{2})
  2. Evaluate Summation: Evaluate the summation by plugging in the values of tt from 00 to 33 into the expression and summing them up.\newlineFor t=0t=0: (59(0)2)=5(-5-9(0)^2) = -5\newlineFor t=1t=1: (59(1)2)=59=14(-5-9(1)^2) = -5-9 = -14\newlineFor t=2t=2: (59(2)2)=59(4)=536=41(-5-9(2)^2) = -5-9(4) = -5-36 = -41\newlineFor t=3t=3: 0000\newlineNow, sum these values: 0011
  3. Perform Addition: Perform the addition to find the sum of the values. 5+(14)+(41)+(86)=5144186=146-5 + (-14) + (-41) + (-86) = -5 - 14 - 41 - 86 = -146

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