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Evaluate the summation below. sum_(i=0)^(3)(-i^(2)-5i) Answer:

Evaluate the summation below.\newline∑i=03(−i2−5i) \sum_{i=0}^{3}\left(-i^{2}-5 i\right) \newlineAnswer:

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Q. Evaluate the summation below.\newline∑i=03(−i2−5i) \sum_{i=0}^{3}\left(-i^{2}-5 i\right) \newlineAnswer:
  1. Evaluate i=0i = 0: Evaluate the expression for i=0i = 0.(−02−5⋅0)=0\left(-0^2 - 5\cdot0\right) = 0
  2. Evaluate i=1i = 1: Evaluate the expression for i=1i = 1.(−12−5⋅1)=−1−5=−6(-1^2 - 5\cdot 1) = -1 - 5 = -6
  3. Evaluate i=2i = 2: Evaluate the expression for i=2i = 2.(−22−5×2)=−4−10=−14(-2^2 - 5\times2) = -4 - 10 = -14
  4. Evaluate i=3i = 3: Evaluate the expression for i=3i = 3.(−32−5×3)=−9−15=−24(-3^2 - 5\times3) = -9 - 15 = -24
  5. Sum results: Sum the results from steps 11 to 44.\newline0+(−6)+(−14)+(−24)=−440 + (-6) + (-14) + (-24) = -44

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