Evaluate the summation below. sum_(d=1)^(4)(2d^(2)-9) Answer:

Evaluate d=1: Evaluate the summation for d=1. The expression is 2d^2 - 9. When d=1, the expression becomes 2(1)^2 - 9 = 2(1) - 9 = 2 - 9 = -7.Evaluate d=2: Evaluate the summation for d=2. The expression is 2d^2 - 9. When d=2, the expression becomes 2(2)^2 - 9 = 2(4) - 9 = 8 - 9 = -1.Evaluate d=3: Evaluate the summation for d=3. The expression is 2d^2 - 9. When d=3, the expression becomes 2(3)^2 - 9 = 2(9) - 9 = 18 - 9 = 9.Evaluate d=4: Evaluate the summation for d=4. The expression is 2d^2 - 9. When d=4, the expression becomes 2(4)^2 - 9 = 2(16) - 9 = 32 - 9 = 23.Calculate total sum: Add the results from steps 1 to 4 to find the total sum. The total sum is (-7) + (-1) + 9 + 23. Calculating the sum: -7 - 1 + 9 + 23 = -8 + 9 + 23 = 1 + 23 = 24.

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Evaluate the summation below.

sum_(d=1)^(4)(2d^(2)-9)
Answer:

Evaluate the summation below. $\newline$ $\sum_{d=1}^{4}\left(2 d^{2}-9\right)$ $\newline$ Answer:

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Calculus

Evaluate definite integrals using the chain rule

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Q. Evaluate the summation below.

\newline

\sum_{d=1}^{4}\left(2 d^{2}-9\right)

\newline

Answer:

Evaluate $d=1$ : Evaluate the summation for $d=1$ . The expression is $2d^2 - 9$ . When $d=1$ , the expression becomes $2(1)^2 - 9 = 2(1) - 9 = 2 - 9 = -7$ .
Evaluate $d=2$ : Evaluate the summation for $d=2$ . $\newline$ The expression is $2d^2 - 9$ . When $d=2$ , the expression becomes $2(2)^2 - 9 = 2(4) - 9 = 8 - 9 = -1$ .
Evaluate $d=3$ : Evaluate the summation for $d=3$ . The expression is $2d^2 - 9$ . When $d=3$ , the expression becomes $2(3)^2 - 9 = 2(9) - 9 = 18 - 9 = 9$ .
Evaluate $d=4$ : Evaluate the summation for $d=4$ . $\newline$ The expression is $2d^2 - 9$ . When $d=4$ , the expression becomes $2(4)^2 - 9 = 2(16) - 9 = 32 - 9 = 23$ .
Calculate total sum: Add the results from steps $1$ to $4$ to find the total sum. $\newline$ The total sum is $(-7) + (-1) + 9 + 23$ . $\newline$ Calculating the sum: $-7 - 1 + 9 + 23 = -8 + 9 + 23 = 1 + 23 = 24$ .