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Let’s check out your problem:
Evaluate
∫
x
3
+
x
x
+
1
d
x
\int \frac{x^{3}+x}{x+1} d x
∫
x
+
1
x
3
+
x
d
x
.
\newline
Choose
1
1
1
answer:
\newline
(A)
x
3
3
−
x
2
2
+
2
x
−
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}-\frac{x^{2}}{2}+2 x-2 \ln |x+1|+C
3
x
3
−
2
x
2
+
2
x
−
2
ln
∣
x
+
1∣
+
C
\newline
(B)
x
3
3
+
2
x
−
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}+2 x-2 \ln |x+1|+C
3
x
3
+
2
x
−
2
ln
∣
x
+
1∣
+
C
\newline
(C)
x
3
3
−
x
2
2
+
2
x
+
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}-\frac{x^{2}}{2}+2 x+2 \ln |x+1|+C
3
x
3
−
2
x
2
+
2
x
+
2
ln
∣
x
+
1∣
+
C
\newline
(D)
x
3
3
+
x
2
+
2
x
+
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}+x^{2}+2 x+2 \ln |x+1|+C
3
x
3
+
x
2
+
2
x
+
2
ln
∣
x
+
1∣
+
C
View step-by-step help
Home
Math Problems
Calculus
Evaluate definite integrals using the chain rule
Full solution
Q.
Evaluate
∫
x
3
+
x
x
+
1
d
x
\int \frac{x^{3}+x}{x+1} d x
∫
x
+
1
x
3
+
x
d
x
.
\newline
Choose
1
1
1
answer:
\newline
(A)
x
3
3
−
x
2
2
+
2
x
−
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}-\frac{x^{2}}{2}+2 x-2 \ln |x+1|+C
3
x
3
−
2
x
2
+
2
x
−
2
ln
∣
x
+
1∣
+
C
\newline
(B)
x
3
3
+
2
x
−
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}+2 x-2 \ln |x+1|+C
3
x
3
+
2
x
−
2
ln
∣
x
+
1∣
+
C
\newline
(C)
x
3
3
−
x
2
2
+
2
x
+
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}-\frac{x^{2}}{2}+2 x+2 \ln |x+1|+C
3
x
3
−
2
x
2
+
2
x
+
2
ln
∣
x
+
1∣
+
C
\newline
(D)
x
3
3
+
x
2
+
2
x
+
2
ln
∣
x
+
1
∣
+
C
\frac{x^{3}}{3}+x^{2}+2 x+2 \ln |x+1|+C
3
x
3
+
x
2
+
2
x
+
2
ln
∣
x
+
1∣
+
C
Perform Long Division:
Long division
of
x
3
+
x
x^3 + x
x
3
+
x
by
x
+
1
x + 1
x
+
1
to simplify the integrand.
\newline
x
3
+
x
x
+
1
=
x
2
−
x
+
2
−
2
x
+
1
\frac{x^3 + x}{x + 1} = x^2 - x + 2 - \frac{2}{x + 1}
x
+
1
x
3
+
x
=
x
2
−
x
+
2
−
x
+
1
2
Integrate Each Term:
Integrate each term separately.
∫
x
2
d
x
=
x
3
3
\int x^2 \, dx = \frac{x^3}{3}
∫
x
2
d
x
=
3
x
3
,
∫
(
−
x
)
d
x
=
−
x
2
2
\int (-x) \, dx = -\frac{x^2}{2}
∫
(
−
x
)
d
x
=
−
2
x
2
,
∫
2
d
x
=
2
x
\int 2 \, dx = 2x
∫
2
d
x
=
2
x
, \int \left(-\frac{\(2\)}{x + \(1\)}\right) dx = \(-2\ln|x +
1
1
1
|
Combine Integration Results:
Combine the results of the integrations.
x
3
3
−
x
2
2
+
2
x
−
2
ln
∣
x
+
1
∣
+
C
\frac{x^3}{3} - \frac{x^2}{2} + 2x - 2\ln|x + 1| + C
3
x
3
−
2
x
2
+
2
x
−
2
ln
∣
x
+
1∣
+
C
More problems from Evaluate definite integrals using the chain rule
Question
The number of subscribers to a magazine is changing at a rate of
r
(
t
)
r(t)
r
(
t
)
subscribers per month (where
t
t
t
is time in months).
\newline
What does
∫
8
10
r
′
(
t
)
d
t
=
7
\int_{8}^{10} r^{\prime}(t) d t=7
∫
8
10
r
′
(
t
)
d
t
=
7
mean?
\newline
Choose
1
1
1
answer:
\newline
(A) The rate of change of number of subscribers increased by
7
7
7
subscribers per month between
t
=
8
t=8
t
=
8
and
t
=
10
t=10
t
=
10
months.
\newline
(B) As of month
10
10
10
, the magazine had
7
7
7
subscribers.
\newline
(C) The number of subscribers increased by
7
7
7
between
t
=
8
t=8
t
=
8
and
t
=
10
t=10
t
=
10
months.
\newline
(D) The average rate of change in subscribers between month
8
8
8
and month
10
10
10
was
7
7
7
subscribers per month.
Get tutor help
Posted 9 months ago
Question
Consider the following problem:
\newline
The water level under a bridge is changing at a rate of
r
(
t
)
=
40
sin
(
π
t
6
)
r(t)=40 \sin \left(\frac{\pi t}{6}\right)
r
(
t
)
=
40
sin
(
6
π
t
)
centimeters per hour (where
t
t
t
is the time in hours). At time
t
=
3
t=3
t
=
3
, the water level is
91
91
91
centimeters. By how much does the water level change during the
4
th
4^{\text {th }}
4
th
hour?
\newline
Which expression can we use to solve the problem?
\newline
Choose
1
1
1
answer:
\newline
(A)
∫
0
4
r
(
t
)
d
t
\int_{0}^{4} r(t) d t
∫
0
4
r
(
t
)
d
t
\newline
(B)
∫
4
5
r
(
t
)
d
t
\int_{4}^{5} r(t) d t
∫
4
5
r
(
t
)
d
t
\newline
(C)
∫
3
4
r
(
t
)
d
t
\int_{3}^{4} r(t) d t
∫
3
4
r
(
t
)
d
t
\newline
(D)
∫
4
4
r
(
t
)
d
t
\int_{4}^{4} r(t) d t
∫
4
4
r
(
t
)
d
t
Get tutor help
Posted 9 months ago
Question
The base of a solid is the region enclosed by the graphs of
y
=
sin
(
x
)
y=\sin (x)
y
=
sin
(
x
)
and
y
=
4
−
x
y=4-\sqrt{x}
y
=
4
−
x
, between
x
=
2
x=2
x
=
2
and
x
=
7
x=7
x
=
7
.
\newline
Cross sections of the solid perpendicular to the
x
x
x
-axis are rectangles whose height is
2
x
2 x
2
x
.
\newline
Which one of the definite integrals gives the volume of the solid?
\newline
Choose
1
1
1
answer:
\newline
(A)
∫
2
7
[
sin
(
x
)
+
x
−
4
]
⋅
2
x
d
x
\int_{2}^{7}[\sin (x)+\sqrt{x}-4] \cdot 2 x d x
∫
2
7
[
sin
(
x
)
+
x
−
4
]
⋅
2
x
d
x
\newline
(B)
∫
2
7
[
sin
2
(
x
)
−
(
4
−
x
)
2
]
d
x
\int_{2}^{7}\left[\sin ^{2}(x)-(4-\sqrt{x})^{2}\right] d x
∫
2
7
[
sin
2
(
x
)
−
(
4
−
x
)
2
]
d
x
\newline
(C)
∫
2
7
[
4
−
x
−
sin
(
x
)
]
⋅
2
x
d
x
\int_{2}^{7}[4-\sqrt{x}-\sin (x)] \cdot 2 x d x
∫
2
7
[
4
−
x
−
sin
(
x
)]
⋅
2
x
d
x
\newline
(D)
∫
2
7
[
(
4
−
x
)
2
−
sin
2
(
x
)
]
d
x
\int_{2}^{7}\left[(4-\sqrt{x})^{2}-\sin ^{2}(x)\right] d x
∫
2
7
[
(
4
−
x
)
2
−
sin
2
(
x
)
]
d
x
Get tutor help
Posted 9 months ago
Question
(
1
×
(
(
1
2
)
n
−
1
)
)
/
(
(
1
2
)
−
1
)
\left(1\times\left(\left(\frac{1}{2}\right)^n-1\right)\right)\bigg/\left(\left(\frac{1}{2}\right)-1\right)
(
1
×
(
(
2
1
)
n
−
1
)
)
/
(
(
2
1
)
−
1
)
Get tutor help
Posted 8 months ago
Question
Solve
∫
1
(
x
−
2
)
(
x
2
+
x
+
1
)
d
x
\int \frac{1}{(x-2)(x^{2}+x+1)}\,dx
∫
(
x
−
2
)
(
x
2
+
x
+
1
)
1
d
x
.
Get tutor help
Posted 8 months ago
Question
What is the integral of the function
f
(
x
)
=
sin
(
2
x
)
f(x) = \sin(2x)
f
(
x
)
=
sin
(
2
x
)
?
\newline
−
1
2
cos
(
x
)
+
C
\frac{-1}{2}\cos(x) + C
2
−
1
cos
(
x
)
+
C
\newline
1
2
sin
(
x
)
+
C
\frac{1}{2}\sin(x) + C
2
1
sin
(
x
)
+
C
\newline
−
1
2
cos
(
2
x
)
+
C
\frac{-1}{2}\cos(2x) + C
2
−
1
cos
(
2
x
)
+
C
\newline
1
2
sin
(
2
x
)
+
C
\frac{1}{2}\sin(2x) + C
2
1
sin
(
2
x
)
+
C
Get tutor help
Posted 8 months ago
Question
What is the integral of the function
f
(
x
)
=
s
i
n
(
2
x
)
\ f(x) = sin(2x)
f
(
x
)
=
s
in
(
2
x
)
?
\newline
−
1
2
cos
(
x
)
+
C
\frac{-1}{2}\cos(x) + C
2
−
1
cos
(
x
)
+
C
\newline
1
2
sin
(
x
)
+
C
\frac{1}{2} \sin(x) + C
2
1
sin
(
x
)
+
C
\newline
−
1
2
cos
(
2
x
)
+
C
\frac{-1}{2}\cos(2x) + C
2
−
1
cos
(
2
x
)
+
C
\newline
1
2
sin
(
2
x
)
+
c
\frac{1}{2} \sin(2x) + c
2
1
sin
(
2
x
)
+
c
Get tutor help
Posted 8 months ago
Question
Suppose
∫
2
4
f
(
2
x
)
d
x
=
10
\int_{2}^{4} f(2x) \, dx = 10
∫
2
4
f
(
2
x
)
d
x
=
10
. Then
∫
4
8
f
(
u
)
d
u
=
\int_{4}^{8} f(u) \, du =
∫
4
8
f
(
u
)
d
u
=
Get tutor help
Posted 8 months ago
Question
Find
d
d
t
∫
2
t
4
e
x
2
d
x
\frac{d}{dt}\int_{2}^{t^{4}}e^{x^{2}}dx
d
t
d
∫
2
t
4
e
x
2
d
x
Get tutor help
Posted 8 months ago
Question
Evaluate and write the answer in scientific notation:
\newline
(
1.48
×
1
0
3
)
(
7
×
1
0
4
)
÷
8.2
×
1
0
12
(1.48\times10^{3})(7\times10^{4})\div8.2\times10^{12}
(
1.48
×
1
0
3
)
(
7
×
1
0
4
)
÷
8.2
×
1
0
12
Get tutor help
Posted 8 months ago
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