Q. Evaluate ∫−8e−9x+93x+25dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
Simplify integrand: Simplify the integrand.We have the integral of a rational function:∫−8e−9x+93x+25dxWe can divide the numerator by the denominator to simplify the integrand.x+93x+25=3+x+916So the integral becomes:∫−8e−9(3+x+916)dx
Split into two integrals: Split the integral into two separate integrals.∫−8e−9(3+x+916)dx=∫−8e−93dx+∫−8e−9x+916dx
Evaluate first integral: Evaluate the first integral.The integral of a constant is just the constant times the variable, so:∫−8e−93dx=3x evaluated from −8 to e−9.This gives us:3(e−9)−3(−8)=3e−27+24=3e−3
Evaluate second integral: Evaluate the second integral.The integral of x+916 is 16 times the natural log of the absolute value of x+9, so:∫−8e−9x+916dx=16ln∣x+9∣ evaluated from −8 to e−9.This gives us:16ln∣e−9+9∣−16ln∣−8+9∣=16ln∣e∣−16ln∣1∣=16ln(e)−16ln(1)Since ln(e)=1 and ln(1)=0, this simplifies to:16(1)−16(0)=16
Combine results: Combine the results from Step 3 and Step 4.Adding the results from the two integrals, we get:(3e−3)+16=3e+13
Write final answer: Write the final answer in simplest form.The final answer is the sum of the two parts of the integral: 3e+13
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