Q. Evaluate ∫3e3+2x−22x−1dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
Identify Integral Type: Identify the type of integral. We are dealing with an integral of a rational function, which suggests that we might need to use partial fraction decomposition. However, in this case, the numerator is a first-degree polynomial and the denominator is a first-degree polynomial as well, but not factorable. We can simplify the integral by dividing the numerator by the denominator.
Perform Long Division: Perform long division for the integrand (2x−1)/(x−2). When we divide 2x by x, we get 2. Multiplying 2 by (x−2) gives us 2x−4. Subtracting this from 2x−1 gives us a remainder of 3. So, the integral can be rewritten as: ∫(2+3/(x−2))dx from 2x0 to 2x1.
Split into Two Integrals: Split the integral into two separate integrals. ∫(2+x−23)dx=∫2dx+∫x−23dx. We can now integrate each term separately.
Integrate Constant Term: Integrate the first term ∫2dx. The integral of a constant is just the constant times the variable, so: ∫2dx=2x.
Integrate Fraction Term: Integrate the second term ∫x−23dx. The integral of x−a1 is ln∣x−a∣, so: ∫x−23dx=3ln∣x−2∣.
Combine Integral Results: Combine the results of the two integrals.The combined integral is:2x+3ln∣x−2∣.
Evaluate Definite Integral: Evaluate the definite integral from x=3 to x=e3+2. We substitute the upper and lower limits into the antiderivative: (2(e3+2)+3ln∣e3+2−2∣)−(2(3)+3ln∣3−2∣).
Simplify Expression: Simplify the expression.2(e3+2)+3ln(e3)−6−3ln(1) simplifies to:2e3+4+3ln(e3)−6.Since ln(e3)=3 and ln(1)=0, the expression further simplifies to:2e3+4+9−6.
Combine Like Terms: Combine like terms to get the final answer.2e3+4+9−6 simplifies to:2e3+7.
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