Q. Evaluate ∫−2e2−3x+3x+2dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
Identify Integral: Identify the integral to be solved.We need to evaluate the integral of the function (x+2)/(x+3) within the limits of integration from x=−2 to x=e2−3.
Simplify Integrand: Simplify the integrand if possible.The integrand (x+2)/(x+3) can be rewritten as 1+(−1)/(x+3) by dividing each term in the numerator by the denominator.
Split Integral: Split the integral into two simpler integrals.The integral of the sum of two functions is the sum of their integrals. Therefore, we can write:∫x+3x+2dx=∫1dx+∫x+3−1dx
Evaluate First Integral: Evaluate the first integral.The integral of 1 with respect to x is x. So, ∫(1)dx=x.
Evaluate Second Integral: Evaluate the second integral.The integral of (−1)/(x+3) with respect to x is −ln∣x+3∣. So, ∫((−1)/(x+3))dx=−ln∣x+3∣.
Combine Results: Combine the results of the two integrals. The combined result of the integrals is x−ln∣x+3∣.
Apply Limits: Apply the limits of integration.We need to evaluate x−ln∣x+3∣ from x=−2 to x=e2−3.
Calculate Definite Integral: Calculate the definite integral. F(x)=x−ln∣x+3∣F(e2−3)=(e2−3)−ln∣e2−3+3∣F(−2)=(−2)−ln∣−2+3∣Now, we subtract F(−2) from F(e2−3):F(e2−3)−F(−2)=(e2−3)−ln∣e2∣−[(−2)−ln∣1∣]
Simplify Expression: Simplify the expression.Since ln∣e2∣=2 and ln∣1∣=0, we have:(e2−3)−2−[(−2)−0]=e2−3−2+2=e2−3
Write Final Answer: Write the final answer.The final value of the integral is e2−3.
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