Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Evaluate 
int_(1)^(4)(4x^(2)-27 x-5)/(x-7)dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).

Evaluate 144x227x5x7dx \int_{1}^{4} \frac{4 x^{2}-27 x-5}{x-7} d x . Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).

Full solution

Q. Evaluate 144x227x5x7dx \int_{1}^{4} \frac{4 x^{2}-27 x-5}{x-7} d x . Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
  1. Perform Polynomial Long Division: Perform polynomial long division to simplify the integrand.\newlineWe need to divide the polynomial 4x227x54x^2 - 27x - 5 by x7x - 7.
  2. Polynomial Long Division Calculation: Polynomial long division calculation. Dividing 4x24x^2 by xx gives 4x4x. Multiplying (x7)(x - 7) by 4x4x gives 4x228x4x^2 - 28x. Subtracting this from 4x227x4x^2 - 27x gives x5x - 5. Dividing xx by xx gives xx00. Multiplying (x7)(x - 7) by xx00 gives xx33. Subtracting this from x5x - 5 gives xx55. So the division gives us xx66 with a remainder of xx55.
  3. Rewrite Integral with Result: Rewrite the integral with the result of the division.\newlineThe integral becomes:\newline(4x+1)dx+(2x7)dx\int (4x + 1)\,dx + \int \left(\frac{2}{x - 7}\right)\,dx from 11 to 44.
  4. Integrate First Part: Integrate the first part of the integral.\newlineThe integral of 4x+14x + 1 with respect to xx is 2x2+x2x^2 + x.
  5. Integrate Second Part: Integrate the second part of the integral.\newlineThe integral of 2x7\frac{2}{x - 7} with respect to xx is 2lnx7.2\ln|x - 7|.
  6. Combine and Evaluate Definite Integral: Combine the results and evaluate the definite integral from 11 to 44. The integral from 11 to 44 is: (2x2+x)+2lnx7(2x^2 + x) + 2\ln|x - 7| evaluated from 11 to 44.
  7. Evaluate Antiderivative at Upper Limit: Evaluate the antiderivative at the upper limit x=4x = 4. Plugging in x=4x = 4 gives us: (2(4)2+4)+2ln47=(2(16)+4)+2ln3=(32+4)+2ln(3)=36+2ln(3)(2(4)^2 + 4) + 2\ln|4 - 7| = (2(16) + 4) + 2\ln|-3| = (32 + 4) + 2\ln(3) = 36 + 2\ln(3).
  8. Evaluate Antiderivative at Lower Limit: Evaluate the antiderivative at the lower limit x=1x = 1. Plugging in x=1x = 1 gives us: (2(1)2+1)+2ln17=(2(1)+1)+2ln6=(2+1)+2ln(6)=3+2ln(6)(2(1)^2 + 1) + 2\ln|1 - 7| = (2(1) + 1) + 2\ln|-6| = (2 + 1) + 2\ln(6) = 3 + 2\ln(6).
  9. Subtract Lower Limit from Upper Limit: Subtract the value at the lower limit from the value at the upper limit.\newline(36+2ln(3))(3+2ln(6))=33+2ln(3)2ln(6)(36 + 2\ln(3)) - (3 + 2\ln(6)) = 33 + 2\ln(3) - 2\ln(6).
  10. Simplify Using Properties of Logarithms: Simplify the expression using properties of logarithms. \newline2ln(3)2ln(6)2\ln(3) - 2\ln(6) can be simplified using the quotient rule of logarithms: ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right).\newlineSo, 2ln(3)2ln(6)=2ln(36)=2ln(12)2\ln(3) - 2\ln(6) = 2\ln\left(\frac{3}{6}\right) = 2\ln\left(\frac{1}{2}\right).
  11. Combine Logarithms into Single Logarithm: Combine the logarithms into a single logarithm.\newlineThe final answer is 33+2ln(12)33 + 2\ln(\frac{1}{2}).

More problems from Evaluate definite integrals using the chain rule