Q. Evaluate ∫010(3e0.2x+4)dx and express the answer in simplest form.Answer:
Identify Integral: Identify the integral to be solved.We need to evaluate the integral of the function 3e0.2x+4 with respect to x, from the lower limit of 0 to the upper limit of 10.
Break into Two: Break the integral into two separate integrals.The integral of a sum is the sum of the integrals, so we can write:\int(\(3e^{0.2x} + 4)\,dx = \int 3e^{0.2x}\,dx + \int 4\,dx
Evaluate First Integral: Evaluate the first integral ∫3e(0.2x)dx. To integrate 3e(0.2x), we recognize that the derivative of 0.2x is 0.2, so we need to divide by 0.2 to compensate for the chain rule when taking the antiderivative: \int \(3e^{(0.2x)}\,dx = \left(\frac{3}{0.2}\right)\int e^{(0.2x)}(0.2\,dx) = 15\int e^{(0.2x)}\,d(0.2x) = 15e^{(0.2x)} + C
Evaluate Second Integral: Evaluate the second integral ∫4dx. The antiderivative of a constant is just the constant times the variable of integration: ∫4dx=4x+C
Combine Results: Combine the results of Step 3 and Step 4.The combined indefinite integral is:15e0.2x+4x+C
Apply Fundamental Theorem: Apply the Fundamental Theorem of Calculus to evaluate the definite integral from 0 to 10. We need to evaluate the combined expression at the upper limit of 10 and subtract the evaluation at the lower limit of 0: (15e(0.2⋅10)+4⋅10)−(15e(0.2⋅0)+4⋅0)
Perform Calculations: Perform the calculations for the upper and lower limits.For the upper limit x=10:15e(0.2⋅10)+4⋅10=15e2+40For the lower limit x=0:15e(0.2⋅0)+4⋅0=15e0+0=15⋅1+0=15
Subtract Lower Limit: Subtract the lower limit evaluation from the upper limit evaluation.(15e2+40)−15=15e2+40−15=15e2+25
Simplify Final Answer: Simplify the final answer.The final answer is 15e2+25.
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