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Let’s check out your problem:
Evaluate:
\newline
(
8
−
6.24
)
2
(8-6.24)2
(
8
−
6.24
)
2
View step-by-step help
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Math Problems
Precalculus
Evaluate rational exponents
Full solution
Q.
Evaluate:
\newline
(
8
−
6.24
)
2
(8-6.24)2
(
8
−
6.24
)
2
Calculate Subtraction Result:
Calculate the subtraction inside the parentheses.
\newline
8
−
6.24
=
1.76
8 - 6.24 = 1.76
8
−
6.24
=
1.76
Multiply by
2
2
2
:
Multiply the result by
2
2
2
.
\newline
1.76
×
2
=
3.52
1.76 \times 2 = 3.52
1.76
×
2
=
3.52
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Let
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y
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x^{2}-y^{2}=28
x
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y
2
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\newline
What is the value of
d
2
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d
x
2
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2
d
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Question
Let
f
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2
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2
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f(x)=2 \cos \left(\frac{x}{2}\right)
f
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x
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f
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x
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x
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1
1
answer:
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(A)
−
cos
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(B)
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(C)
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x
2
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(D)
−
1
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x
2
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2
1
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(
2
x
)
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Question
Last week, the thickness of the ice on a lake increased by
25
t
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3
\frac{25}{t+3}
t
+
3
25
centimeters per day (where
t
t
t
is the number of days since the ice first formed).
\newline
By how many centimeters did the thickness of the ice increase between
t
=
0
t=0
t
=
0
and
t
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4
t=4
t
=
4
?
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1
1
1
answer:
\newline
(A)
1
,
000
441
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441
1
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(B)
100
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3
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25
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3
7
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(D)
25
ln
(
4
)
25 \ln (4)
25
ln
(
4
)
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Question
What is the area of the region bound by the graphs of
f
(
x
)
=
−
x
2
,
g
(
x
)
=
3
x
−
10
f(x)=-x^{2}, g(x)=3 x-10
f
(
x
)
=
−
x
2
,
g
(
x
)
=
3
x
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10
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x
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0
x=0
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\newline
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1
1
1
answer:
\newline
2
2
2
\newline
8
3
\frac{8}{3}
3
8
\newline
(C)
16
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(D)
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Question
Let
f
f
f
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f
(
1
)
=
−
7
f(1)=-7
f
(
1
)
=
−
7
,
f
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(
1
)
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0
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(
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0
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f
′
′
(
1
)
=
−
2
f^{\prime \prime}(1)=-2
f
′′
(
1
)
=
−
2
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\newline
What occurs in the graph of
f
f
f
at the point
(
1
,
−
7
)
(1,-7)
(
1
,
−
7
)
?
\newline
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1
1
1
answer:
\newline
(A)
(
1
,
−
7
)
(1,-7)
(
1
,
−
7
)
is a minimum point.
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(B)
(
1
,
−
7
)
(1,-7)
(
1
,
−
7
)
is a maximum point.
\newline
(C) There's not enough information to tell.
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Posted 9 months ago
Question
Let
f
f
f
be a twice differentiable function, and let
f
(
−
3
)
=
−
4
f(-3)=-4
f
(
−
3
)
=
−
4
,
f
′
(
−
3
)
=
0
f^{\prime}(-3)=0
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′
(
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)
=
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f
′
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(
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3
)
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1
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\newline
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f
f
f
at the point
(
−
3
,
−
4
)
(-3,-4)
(
−
3
,
−
4
)
?
\newline
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1
1
1
answer:
\newline
(A)
(
−
3
,
−
4
)
(-3,-4)
(
−
3
,
−
4
)
is a minimum point.
\newline
(B)
(
−
3
,
−
4
)
(-3,-4)
(
−
3
,
−
4
)
is a maximum point.
\newline
(C) There's not enough information to tell.
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Question
What is the area of the region between the graphs of
f
(
x
)
=
x
2
−
4
x
+
1
f(x)=x^{2}-4 x+1
f
(
x
)
=
x
2
−
4
x
+
1
and
g
(
x
)
=
3
x
−
5
g(x)=3 x-5
g
(
x
)
=
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x
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5
from
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1
x=1
x
=
1
to
x
=
4
x=4
x
=
4
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\newline
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1
1
1
answer:
\newline
(A)
125
6
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6
125
\newline
(B)
27
2
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2
27
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(C)
4
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4
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(D)
81
2
\frac{81}{2}
2
81
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Question
What is the area of the region between the graphs of
f
(
x
)
=
x
2
−
3
x
f(x)=x^{2}-3 x
f
(
x
)
=
x
2
−
3
x
and
g
(
x
)
=
2
x
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g
(
x
)
=
2
x
from
x
=
0
x=0
x
=
0
to
x
=
5
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x
=
5
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\newline
Choose
1
1
1
answer:
\newline
(A)
175
6
\frac{175}{6}
6
175
\newline
(B)
25
25
25
\newline
(C)
325
6
\frac{325}{6}
6
325
\newline
(D)
125
6
\frac{125}{6}
6
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Question
What is the area of the region bound by the graphs of
f
(
x
)
=
x
−
2
,
g
(
x
)
=
14
−
x
f(x)=\sqrt{x-2}, g(x)=14-x
f
(
x
)
=
x
−
2
,
g
(
x
)
=
14
−
x
, and
x
=
2
x=2
x
=
2
?
\newline
Choose
1
1
1
answer:
\newline
(A)
99
2
\frac{99}{2}
2
99
\newline
(B)
19
6
\frac{19}{6}
6
19
\newline
(C)
151
2
\frac{151}{2}
2
151
\newline
(D)
45
2
\frac{45}{2}
2
45
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Posted 9 months ago
Question
d
d
x
[
x
3
sin
(
x
)
]
=
\frac{d}{d x}\left[\frac{x^{3}}{\sin (x)}\right]=
d
x
d
[
s
i
n
(
x
)
x
3
]
=
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Posted 9 months ago
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