Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function S(t) of time t (in days) using a sinusoidal expression of the form a*sin(b*t)+d. On day t=0, the stock is at its average value of $3.47 per share, but 91.25 days later, its value is down to its minimum of $1.97. Find S(t). t should be in radians. S(t)=

Given Average Value: The stock's average value is given at t=0, which is the midline of the sinusoidal function. So d = $3.47.Calculate Period: Since the stock reaches its minimum value 91.25 days later, this corresponds to a quarter of the sinusoidal period. Therefore, the period P = 91.25 * 4 days.Calculate b: Calculate the value of b, which is related to the period by the formula b = 2π/P. So b = 2π/(91.25 * 4).Calculate Amplitude: The amplitude a is the difference between the average value and the minimum value. So a = $3.47 - $1.97.Calculate a: Calculate the amplitude a. a = $3.47 - $1.97 = $1.50.Write Function S(t): Now we have all the parameters to write down the function S(t). S(t) = a*sin(b*t) + d.Substitute Values: Substitute the values of a, b, and d into the function. S(t) = 1.50*sin((2π/(91.25 * 4))*t) + 3.47.Simplify Expression for b: Simplify the expression for b. b = 2π/(91.25 * 4) = 2π/365.Final Function S(t): Write the final function S(t). S(t) = 1.50*sin((2π/365)*t) + 3.47.

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Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function $S(t)$ of time $t$ (in days) using a sinusoidal expression of the form $a \cdot \sin (b \cdot t)+d$ . $\newline$ On day $t=0$ , the stock is at its average value of $\$ 3.47$ per share, but $91$ . $25$ days later, its value is down to its minimum of $\$ 1.97$ . $\newline$ Find $S(t)$ . $\newline$ $t$ should be in radians. $\newline$ $S(t)=$

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Q. Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function

S(t)

of time

t

(in days) using a sinusoidal expression of the form

a \cdot \sin (b \cdot t)+d

\newline

On day

t=0

, the stock is at its average value of

\$ 3.47

per share, but

91

25

days later, its value is down to its minimum of

\$ 1.97

\newline

Find

S(t)

\newline

t

should be in radians.

\newline

S(t)=

Given Average Value: The stock's average value is given at $t=0$ , which is the midline of the sinusoidal function. So $d = \$3.47$ .
Calculate Period: Since the stock reaches its minimum value $91.25$ days later, this corresponds to a quarter of the sinusoidal period. Therefore, the period $P = 91.25 \times 4$ days.
Calculate b: Calculate the value of b, which is related to the period by the formula $b = \frac{2\pi}{P}$ . So $b = \frac{2\pi}{91.25 \times 4}$ .
Calculate Amplitude: The amplitude $a$ is the difference between the average value and the minimum value. So $a = \$3.47 - \$1.97$ .
Calculate $a$ : Calculate the amplitude $a$ . $a = (\$)3.47 - (\$)1.97 = (\$)1.50$ .
Write Function $S(t)$ : Now we have all the parameters to write down the function $S(t)$ . $S(t) = a\sin(b\cdot t) + d$ .
Substitute Values: Substitute the values of $a$ , $b$ , and $d$ into the function. $S(t) = 1.50\cdot\sin\left(\frac{2\pi}{91.25 \cdot 4}\cdot t\right) + 3.47$ .
Simplify Expression for $b$ : Simplify the expression for $b$ . $b = \frac{2\pi}{(91.25 \times 4)} = \frac{2\pi}{365}$ .
Final Function S(t): Write the final function S(t). $S(t) = 1.50\cdot\sin\left(\frac{2\pi}{365}\cdot t\right) + 3.47$ .