Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.−x+2y−4x+8yamp;=−5amp;=−23Infinitely Many SolutionsOne SolutionNo Solutions
Q. Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.−x+2y−4x+8y=−5=−23Infinitely Many SolutionsOne SolutionNo Solutions
Check Coefficients Multiples: We are given the system of equations:1) −x+2y=−52) −4x+8y=−23The first step is to check if the two equations are multiples of each other, which would indicate that they are essentially the same line and would have infinitely many solutions if the constants also have the same ratio, or no solutions if they do not.
Find Coefficients Ratio: Let's find the ratio of the coefficients of x and y in both equations.For the first equation, the coefficients are −1 for x and 2 for y.For the second equation, the coefficients are −4 for x and 8 for y.The ratio of the coefficients of x is y1.The ratio of the coefficients of y is y3.Since both ratios are equal, the lines are parallel or the same line. We need to check the constants to determine which case it is.
Compare Constants Ratios: Now let's compare the ratio of the constants in both equations.The constant in the first equation is −5 and in the second equation is −23.The ratio of the constants is −23/−5, which is not equal to 4 (the ratio of the coefficients).Since the ratios of the coefficients are the same, but the ratio of the constants is different, the lines are parallel and do not intersect. This means the system of equations has no solutions.
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