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A brand of cereal had 1.2 milligrams 
(mg) of iron per serving. Then they changed their recipe so they had 
1.8mg of iron per serving.
What was the percent increase in iron?

%

A brand of cereal had 11.22 milligrams (mg) (\mathrm{mg}) of iron per serving. Then they changed their recipe so they had 1.8mg 1.8 \mathrm{mg} of iron per serving.\newlineWhat was the percent increase in iron?\newline% \%

Full solution

Q. A brand of cereal had 11.22 milligrams (mg) (\mathrm{mg}) of iron per serving. Then they changed their recipe so they had 1.8mg 1.8 \mathrm{mg} of iron per serving.\newlineWhat was the percent increase in iron?\newline% \%
  1. Calculate Iron Difference: Calculate the difference in iron content per serving before and after the recipe change.\newlineOriginal iron content: 1.2mg1.2\,\text{mg}\newlineNew iron content: 1.8mg1.8\,\text{mg}\newlineDifference in iron content: 1.8mg1.2mg=0.6mg1.8\,\text{mg} - 1.2\,\text{mg} = 0.6\,\text{mg}
  2. Determine Percent Increase: Determine the percent increase in iron content based on the original iron content.\newlinePercent increase = (Difference in iron content/Original iron content)×100%(\text{Difference in iron content} / \text{Original iron content}) \times 100\%\newlinePercent increase = (0.6mg/1.2mg)×100%(0.6 \, \text{mg} / 1.2 \, \text{mg}) \times 100\%
  3. Perform Calculation: Perform the calculation to find the percent increase.\newlinePercent increase = (0.6/1.2)×100%(0.6 / 1.2) \times 100\%\newlinePercent increase = 0.5×100%0.5 \times 100\%\newlinePercent increase = 50%50\%