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What is the result of subtracting the second equation from the first? {:[x-3y=6],[-8x-y=6]:}

What is the result of subtracting the second equation from the first?\newlinex−3y=6−8x−y=6 \begin{array}{r} x-3 y=6 \\ -8 x-y=6 \end{array}

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Full solution

Q. What is the result of subtracting the second equation from the first?\newlinex−3y=6−8x−y=6 \begin{array}{r} x-3 y=6 \\ -8 x-y=6 \end{array}
  1. Write Equations: Write down the equations to be subtracted.\newlineFirst equation: x−3y=6x - 3y = 6\newlineSecond equation: −8x−y=6-8x - y = 6
  2. Subtract Equations: Subtract the second equation from the first equation.\newline(x−3y)−(−8x−y)=6−6(x - 3y) - (-8x - y) = 6 - 6\newlineThis simplifies to x−3y+8x+y=0x - 3y + 8x + y = 0
  3. Combine Like Terms: Combine like terms.x+8x−3y+y=0x + 8x - 3y + y = 09x−2y=09x - 2y = 0
  4. Final Result: Write the final result of the subtraction.\newlineThe result of subtracting the second equation from the first is 9x−2y=09x - 2y = 0.

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