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What is the result of subtracting the second equation from the first?

{:[-7x-y=0],[7x+8y=-6]:}

What is the result of subtracting the second equation from the first?\newline7xyamp;=07x+8yamp;=6 \begin{aligned} -7 x-y & =0 \\ 7 x+8 y & =-6 \end{aligned}

Full solution

Q. What is the result of subtracting the second equation from the first?\newline7xy=07x+8y=6 \begin{aligned} -7 x-y & =0 \\ 7 x+8 y & =-6 \end{aligned}
  1. Write Equations: First, let's write down the equations we are working with for clarity:\newline11) 7xy=0-7x - y = 0\newline22) 7x+8y=67x + 8y = -6\newlineWe are asked to subtract the second equation from the first. This means we will subtract each corresponding term in the second equation from the first equation.
  2. Subtract Second Equation: To subtract the second equation from the first, we perform the operation on each term:\newline(7x)(7x)=7x7x(-7x) - (7x) = -7x - 7x\newline(y)(8y)=y8y(-y) - (8y) = -y - 8y\newline(0)(6)=0+6(0) - (-6) = 0 + 6\newlineSo, the operation will look like this: (7x7x)+(y8y)=0+6(-7x - 7x) + (-y - 8y) = 0 + 6
  3. Perform Operation: Now, let's simplify the terms:\newline7x7x=14x-7x - 7x = -14x\newliney8y=9y-y - 8y = -9y\newline0+6=60 + 6 = 6\newlineSo, the simplified form of the subtraction is: 14x9y=6-14x - 9y = 6

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