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We want to solve the following system of equations.

{[y=4x(x-2)],[x+y=2]:}
One of the solutions to this system is 
(2,0).
Find the other solution.
Your answer must be exact.

We want to solve the following system of equations.\newline{y=4x(x2)x+y=2 \left\{\begin{array}{l} y=4 x(x-2) \\ x+y=2 \end{array}\right. \newlineOne of the solutions to this system is (2,0) (2,0) .\newlineFind the other solution.\newlineYour answer must be exact.

Full solution

Q. We want to solve the following system of equations.\newline{y=4x(x2)x+y=2 \left\{\begin{array}{l} y=4 x(x-2) \\ x+y=2 \end{array}\right. \newlineOne of the solutions to this system is (2,0) (2,0) .\newlineFind the other solution.\newlineYour answer must be exact.
  1. Substitute and simplify: Substitute the expression for yy from the first equation into the second equation.\newlineWe have y=4x(x2)y = 4x(x - 2) and x+y=2x + y = 2. Substituting yy in the second equation gives us x+4x(x2)=2x + 4x(x - 2) = 2.
  2. Expand and combine like terms: Expand the equation x+4x(x2)=2x + 4x(x - 2) = 2.\newlineThis gives us x+4x28x=2x + 4x^2 - 8x = 2.
  3. Factor the quadratic equation: Simplify the equation by combining like terms.\newlineThis results in 4x27x+2=04x^2 - 7x + 2 = 0.
  4. Solve for x: Factor the quadratic equation 4x27x+2=04x^2 - 7x + 2 = 0.\newlineThe factors of this quadratic equation are (4x1)(x2)=0(4x - 1)(x - 2) = 0.
  5. Substitute and simplify: Solve for xx by setting each factor equal to zero.\newlineSetting 4x1=04x - 1 = 0 gives us x=14x = \frac{1}{4}.\newlineSetting x2=0x - 2 = 0 gives us x=2x = 2, but we already know that (2,0)(2,0) is one solution, so we are looking for the other solution.
  6. Check the solution: Substitute x=14x = \frac{1}{4} into the first equation to find the corresponding value of yy.\newlineSubstituting into y=4x(x2)y = 4x(x - 2) gives us y=4(14)((14)2)y = 4 \cdot \left(\frac{1}{4}\right) \cdot \left(\left(\frac{1}{4}\right) - 2\right).
  7. Check the solution: Substitute x=14x = \frac{1}{4} into the first equation to find the corresponding value of yy. Substituting into y=4x(x2)y = 4x(x - 2) gives us y=4(14)((14)2)y = 4 \cdot \left(\frac{1}{4}\right) \cdot \left(\left(\frac{1}{4}\right) - 2\right). Simplify the expression to find the value of yy. This gives us y=4(14)(74)y = 4 \cdot \left(\frac{1}{4}\right) \cdot \left(-\frac{7}{4}\right), which simplifies to y=7y = -7.
  8. Check the solution: Substitute x=14x = \frac{1}{4} into the first equation to find the corresponding value of yy.\newlineSubstituting into y=4x(x2)y = 4x(x - 2) gives us y=4(14)((14)2)y = 4 \cdot \left(\frac{1}{4}\right) \cdot \left(\left(\frac{1}{4}\right) - 2\right). Simplify the expression to find the value of yy.\newlineThis gives us y=4(14)(74)y = 4 \cdot \left(\frac{1}{4}\right) \cdot \left(-\frac{7}{4}\right), which simplifies to y=7y = -7. Check the solution (14,7)\left(\frac{1}{4}, -7\right) in the second equation x+y=2x + y = 2.\newlineSubstituting x=14x = \frac{1}{4} and y=7y = -7 into the equation gives us yy11, which simplifies to yy22. There is a math error in the previous steps.