We want to solve the following system of equations. {[x^(2)+y^(2)=1],[y=2x+2]:} One of the solutions to this system is (-1,0). Find the other solution. Your answer must be exact.

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We want to solve the following system of equations.  {[x^(2)+y^(2)=1],[y=2x+2]:} One of the solutions to this system is  (-1,0). Find the other solution. Your answer must be exact.

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Given Equations: We are given the system of equations: 1. x^2 + y^2 = 1 2. y = 2x + 2 We need to find the solution to this system other than (-1,0).Substituting y in the first equation: Substitute the expression for y from the second equation into the first equation to eliminate y and solve for x. So, we replace y in the first equation with (2x + 2) to get: x^2 + (2x + 2)^2 = 1Expanding the squared term: Expand the squared term (2x + 2)^2 to simplify the equation: x^2 + (4x^2 + 8x + 4) = 1Combining like terms: Combine like terms to form a quadratic equation: x^2 + 4x^2 + 8x + 4 = 1 5x^2 + 8x + 4 = 1Setting the quadratic equation to zero: Subtract 1 from both sides to set the quadratic equation to zero: 5x^2 + 8x + 4 - 1 = 0 5x^2 + 8x + 3 = 0Factoring the quadratic equation: Factor the quadratic equation to find the values of x: (5x + 3)(x + 1) = 0Solving for x: Set each factor equal to zero and solve for x: 5x + 3 = 0 or x + 1 = 0 x = -3/5 or x = -1 Since we already know that x = -1 is part of the solution (-1,0), we will use x = -3/5 for the other solution.Substituting x into the second equation: Substitute x = -3/5 into the second equation y = 2x + 2 to find the corresponding value of y: y = 2(-3/5) + 2 y = -6/5 + 2 y = -6/5 + 10/5 y = 4/5Final Solution: The other solution to the system of equations is (-3/5, 4/5).

We want to solve the following system of equations. $\newline$ $\left\{\begin{array}{l} x^{2}+y^{2}=1 \\ y=2 x+2 \end{array}\right.$ $\newline$ One of the solutions to this system is $(-1,0)$ . $\newline$ Find the other solution. Your answer must be exact.

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We want to solve the following system of equations.\newline{x2+y2=1y=2x+2 \left\{\begin{array}{l} x^{2}+y^{2}=1 \\ y=2 x+2 \end{array}\right. {x2+y2=1y=2x+2​\newlineOne of the solutions to this system is (−1,0) (-1,0) (−1,0).\newlineFind the other solution. Your answer must be exact.

We want to solve the following system of equations. $\newline$ $\left\{\begin{array}{l} x^{2}+y^{2}=1 \\ y=2 x+2 \end{array}\right.$ $\newline$ One of the solutions to this system is $(-1,0)$ . $\newline$ Find the other solution. Your answer must be exact.